Question

The voltage in a lightbulb is given by the equation V=IR. In this equation, V is the voltage, I is the current, and R is the resistance. What is the current in a lightbulb with a voltage of 35.0 V and a resistance of 175 ohms?

a. 6125 A
b. 0.200 A
c. 1.40 A
d. 5.00 A

Answer 1

The current in a lightbulb with a voltage of 35.0 V and a resistance of 175 ohms is 0.20 A.

Step-by-step explanation:

To calculate the current in a lightbulb with a voltage of 35.0 V and a resistance of 175 ohms, we can use Ohm's Law, which states that V (voltage) is equal to I (current) multiplied by R (resistance). Rearranging the equation, we have I = V / R.

Substituting the given values, we get I = 35.0 V / 175 ohms = 0.20 A.

Therefore, the current in the lightbulb is 0.20 A, which corresponds to option b. 0.200 A in the answer choices.