Final answer:
The period of Susan's simple pendulum with a 24.6-centimeter-long string is approximately 0.99 seconds. This is calculated using the formula T = 2π√(l/g), where l is 0.246 meters and g is 9.80 m/s².
Step-by-step explanation:
The question asks about the period of a simple pendulum that Susan made, which consists of a rock attached to a 24.6-centimeter-long string. The period of a pendulum is determined by the formula T = 2π√(l/g), where T is the period, l is the length of the string in meters, and g is the acceleration due to gravity, approximately 9.80 m/s² on the surface of the Earth. In this case, the length should be converted to meters, so l = 0.246 m. Plugging these values into the formula, we can find the period T.
Calculating the period, we get: T = 2π√(0.246/9.80), which after calculating, gives a value close to option B, 0.99 seconds. This is the period of Susan's pendulum. Keep in mind that for a small angular displacement, the motion of the pendulum is a simple harmonic motion and thus follows this formula for period. The length of the pendulum is the predominant factor that affects its oscillation period in simple harmonic motion.