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Alita is 2 times as old as Jiro. Jiro is 4 years younger than Erik. Erik is 1/3 as old as Dawn. The sum of all their ages is 72. What equation could you write to represent this situation? Show your work. What is the solution of your equation? Show your work.

A) 72
2x+x+(x+4)+3x=72
B) 2x+x−(x+4)+3x=72
C) 2x+(x+4)+3/1(x+4)=72
D) 2x+x+(x−4)+ 3/2(x−4)=72

1 Answer

1 vote

Final answer:

The correct equation to represent the situation is 2x + x + (x + 4) + 3(x + 4) = 72. By defining 'x' as Jiro's age and expressing the other ages in terms of 'x', we find that Jiro is 8 years old, which allows us to calculate everyone's age.

Step-by-step explanation:

To solve the age problem, we need to use algebra to create an equation that represents the situation. We know that Alita is 2 times as old as Jiro, Jiro is 4 years younger than Erik, Erik is 1/3 as old as Dawn, and the sum of all their ages is 72 years. Let's denote the ages of Alita, Jiro, Erik, and Dawn with the variables A, J, E, and D respectively.

From the given information we can say:

  • A = 2J (Alita is 2 times as old as Jiro)
  • J = E - 4 (Jiro is 4 years younger than Erik)
  • E = D/3 (Erik is 1/3 as old as Dawn)

In terms of Jiro's age (let's use 'x' for Jiro's age), we can rewrite these equations as:

  • A = 2x
  • E = x + 4
  • D = 3E = 3(x + 4)

The sum of their ages is 72, so we have the equation: 2x + x + (x + 4) + 3(x + 4) = 72.

This simplifies to: 2x + x + x + 4 + 3x + 12 = 72. Combining like terms results in: 7x + 16 = 72. Subtracting 16 from both sides gives us 7x = 56, and dividing both sides by 7 yields x = 8.

Therefore, Jiro is 8 years old, Alita is 16 years old (2 x 8), Erik is 12 years old (8 + 4), and Dawn is 36 years old (3 x (8 + 4)).

User Tom Schaefer
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