Question

Aiden ordered six hamburgers and five orders of fries for his lunch buddies and spent a total of $56 harper orders four hamburgers and one order fries to share with her friends she spends a total of $28 write a system of equations and solve for the price of a burger b and the price of an order of fries f. how much would it cost if you ordered one burger and one order of fries? Aiden's order: 6b+5f=56

Harper's order: 4b+1f=28

Options:

a) b=4,f=7

b) b=7,f=4

c) b=5,f=6

d) b=6,f=5

Answer 1

The price of a burger is $6 and the price of an order of fries is $4. If you ordered one burger and one order of fries, it would cost $10.

Step-by-step explanation:

To solve this system of equations, we can set up a system of equations based on the given information:

Aiden's order: 6b + 5f = 56

Harper's order: 4b + 1f = 28

To solve this system, we can use the method of substitution or elimination. Let's use the method of substitution:

First, solve one of the equations for one variable in terms of the other. Let's solve the second equation for f:

4b + f = 28

f = 28 - 4b

Now, substitute the value of f in the first equation:

6b + 5(28 - 4b) = 56

6b + 140 - 20b = 56

-14b + 140 = 56

-14b = -84

b = -84/-14

b = 6

Now, substitute the value of b in the second equation:

4(6) + f = 28

24 + f = 28

f = 28 - 24

f = 4

The price of a burger (b) is $6 and the price of an order of fries (f) is $4.

If you ordered one burger and one order of fries, it would cost $6 + $4 = $10.