Final answer:
The concentration of the tartaric acid solution is 0.163 M.
Step-by-step explanation:
To determine the concentration of the tartaric acid solution, we can use the stoichiometry of the reaction between tartaric acid and LiOH. The balanced equation for the reaction is:
H₂C₄H₄O₆ + 2LiOH → Li₂C₄H₄O₆ + 2H₂O
From the equation, we can see that 1 mole of tartaric acid reacts with 2 moles of LiOH. We are given that 32.0 mL of 0.805 M LiOH is required to reach the second equivalence point.
Using this information, we can calculate the moles of LiOH used in the titration:
Moles of LiOH = concentration × volume = (0.805 M)(0.0320 L) = 0.0258 moles
Since 2 moles of LiOH react with 1 mole of tartaric acid, the moles of tartaric acid in the titration is:
Moles of tartaric acid = 0.0258 moles × (1/2) = 0.0129 moles
Finally, to find the concentration of the tartaric acid solution, we divide the moles of tartaric acid by the volume of the solution:
Concentration = moles/volume = 0.0129 moles/0.0790 L = 0.163 M