Question

You shoot a cannonball off the side of the cliff. The cannonball leaves the cannon at 30 m/s, and it lands 50 meters away. How tall is the cliff?

a. 10 meters
b. 20 meters
c. 25 meters
d. 30 meters

Answer 1

The height of the cliff is 9.15 meters.

Step-by-step explanation:

To find the height of the cliff, we can use the equation of projectile motion. Since the cannonball is launched horizontally, its initial vertical velocity is 0 m/s. The time it takes for the cannonball to fall can be found using the equation:

t = sqrt((2 * h) / g)

Where t is the time, h is the height, and g is the acceleration due to gravity (9.8 m/s^2).

Plugging in the values, we get:

2.35 = sqrt((2 * h) / 9.8)

Squaring both sides of the equation, we have:

(2.35)^2 = (2 * h) / 9.8

Simplifying the equation, we get:

h = ((2.35)^2 * 9.8) / 2 = 9.15 m

Therefore, the height of the cliff is 9.15 meters.