Final answer:
The mass of propane that can burn in 480.8g of oxygen is calculated by using the balanced chemical equation for the complete combustion of propane, figuring out the mole ratio between propane and oxygen, and converting the moles of propane to grams. The calculated mass of propane is 132.52g, which is not listed in the provided options.
Step-by-step explanation:
To determine the mass of propane that can burn in 480.8g of oxygen, we first need to write down the balanced chemical equation for the combustion of propane:
C3H8 + 5 O2 → 3 CO2 + 4 H2O
From the equation, we can see that 1 mole of propane (C3H8) reacts with 5 moles of oxygen (O2) to produce 3 moles of carbon dioxide (CO2) and 4 moles of water (H2O). Now, we need to use the molar masses of propane and oxygen to do the conversion:
Step 1: Calculate moles of O2:
480.8 g O2 × (1 mol O2 / 32.00 g O2) = 15.025 mol O2
Step 2: From the balanced equation, the mole ratio of C3H8 to O2 is 1:5. Therefore:
15.025 mol O2 × (1 mol C3H8 / 5 mol O2) = 3.005 mol C3H8
Step 3: Finally, we convert moles of propane back to grams:
3.005 mol C3H8 × (44.10 g C3H8 / 1 mol C3H8) = 132.52 g C3H8
This mass is not listed in the options provided, which suggests there might be a mistake in the question or answer choices. If those are the only options available, none of them would be correct based on this calculation.