7.6k views
0 votes
What is the partial fraction decomposition of (7x^2 - 6x + 9) / (3x(4x^2 + 9))? Please select the correct partial fraction decomposition from the options provided.

a) 1/(3x)
b) (x - 2)/(4x² + 9)
c) 1/(3x)
d) (x + 2)/(4x² + 9)
e) -2/(3x)
f) (x - 1)/(4x² + 9)
g) -2/(3x)
h) (x + 1)/(4x² + 9)

User Lomec
by
8.0k points

1 Answer

5 votes

Final answer:

The partial fraction decomposition of (7x² - 6x + 9) / (3x(4x² + 9)) is (x + 2)/(4x² + 9).

Step-by-step explanation:

The partial fraction decomposition of (7x² - 6x + 9) / (3x(4x² + 9)) is d) (x + 2)/(4x² + 9).

To find the partial fraction decomposition, we first factor the denominator as (4x² + 9) = (2x + 3i)(2x - 3i), where i is the imaginary unit. Then, we write the fraction as A/(3x) + (Bx + C)/(2x + 3i) + (Dx + E)/(2x - 3i), where A, B, C, D, and E are constants to be determined. We then multiply both sides by the denominator and solve for the constants.

In this case, the solution is (x + 2)/(4x² + 9).

User SMeyers
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories