Final answer:
The equation of the perpendicular line to y = 34x - 8 passing through the point (-12, 1) is y = -1/34x + 22/34.
Step-by-step explanation:
To find the equation of the line perpendicular to y = 34x - 8 and passes through the point (-12, 1), we need to find the negative reciprocal of the slope of the given line. The given line has a slope of 34, so the perpendicular line will have a slope of -1/34. Using the point-slope form of a linear equation, we can write the equation of the perpendicular line as:
y - 1 = -1/34(x + 12)
Let's simplify this equation:
y - 1 = -1/34x - 12/34
y = -1/34x - 12/34 + 1
y = -1/34x - 12/34 + 34/34
y = -1/34x + 22/34
Therefore, the equation of the line that is perpendicular to y = 34x - 8 and contains the point (-12, 1) is y = -1/34x + 22/34.