Final answer:
The bus travels 120 meters in 4 seconds while decelerating with a uniform acceleration of -10 m/s². The calculation uses the kinematic equation s = ut + ½at², where s is displacement, u is initial velocity, t is time, and a is acceleration.
Step-by-step explanation:
To determine how far the bus travels in 4 seconds while decelerating, we use the kinematic equation for uniformly accelerated motion:
s = ut + ½at²
where:
- s is the displacement (distance traveled)
- u is the initial velocity (50 m/s)
- t is the time (4 seconds)
- a is the acceleration (-10 m/s² due to deceleration)
Plugging the values into the equation gives:
s = (50 m/s * 4 s) + ½(-10 m/s² * (4 s)²)
s = (200 m) + ½(-160 m)
s = 200 m - 80 m
s = 120 m
Therefore, the bus travels 120 meters in 4 seconds while decelerating at -10 m/s².