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Point F is on line segment EG. Given EF=2x−2, FG=5x+1, and EG=5x+7, determine the numerical length of segment EF.

a) 3x+5
b) 3x−5
c) 7x−9
d) 7x+5
e) 3x−7

1 Answer

2 votes

Final answer:

The length of segment EF is found to be 6 meters by setting up the equation EF + FG = EG and solving for x first before substituting it back into the expression for EF.

Step-by-step explanation:

To determine the numerical length of segment EF, we first need to recognize that EF + FG = EG because F is a point on line segment EG. Given the information EF = 2x - 2, FG = 5x + 1, and EG = 5x + 7, we can set up the following equation:

EF + FG = EG
(2x - 2) + (5x + 1) = (5x + 7)

Now, let's simplify and solve for x:

2x - 2 + 5x + 1 = 5x + 7
7x - 1 = 5x + 7

By subtracting 5x from both sides, we get:

2x - 1 = 7
2x = 8
x = 4

Having found the value of x, we can now substitute it back into the expression for EF:

EF = 2x - 2
EF = 2(4) - 2
EF = 8 - 2
EF = 6

Therefore, the length of segment EF is 6 meters.

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