Question

What distance does an airplane travel when speeding up to 122 m/s for 6.5 s to accelerate the plane?

A) 225.5 meters
B) 363.04 meters
C) 511.25 meters
D) 678.5 meters
E) 789.12 meters

Answer 1

The distance the airplane travels when speeding up to 122 m/s for 6.5 s is approximately 396.5 meters.

Step-by-step explanation:

To find the distance an airplane travels when accelerating, we can use the formula:

distance = initial velocity x time + (1/2) x acceleration x time^2

In this case, the initial velocity is 0 m/s since the airplane starts from rest, the acceleration is calculated from the given final velocity and time:

acceleration = (final velocity - initial velocity) / time = (122 m/s - 0 m/s) / 6.5 s

Once we have the acceleration, we can substitute the values back into the distance formula to calculate:

distance = 0 m/s x 6.5 s + (1/2) x (122 m/s - 0 m/s) / 6.5 s x (6.5 s)^2

Calculating this expression gives us:

distance = 0 m + (61 m/s / 6.5 s) x 6.5^2 s

distance = 61 m/s x 6.5 s

distance = 396.5 meters

Therefore, the distance the airplane travels when speeding up to 122 m/s for 6.5 s is approximately 396.5 meters.