216k views
4 votes
Calls arrive at a switchboard at a mean of one every 15 seconds. If call arrivals follow the exponential distribution, find the 80th percentile for the time between call arrivals.

a. 22.2 seconds
b. 30.7 seconds
c. 45.5 seconds
d. 55.0 seconds

User Matekus
by
6.6k points

1 Answer

2 votes

Final answer:

The 80th percentile for the time between call arrivals at a switchboard, where calls follow the exponential distribution at a mean of one every 15 seconds, is approximately 22.2 seconds.

Step-by-step explanation:

To find the 80th percentile for the time between call arrivals when calls arrive at a switchboard at a mean of one every 15 seconds and follow the exponential distribution, we can use the formula for the exponential distribution's percentile. The exponential distribution function is given by F(x) = 1 - e-λx where λ is the rate of occurrences, which in this case is 1/15, since a call arrives every 15 seconds. To find the 80th percentile (P80), we set the cumulative distribution function to 0.8: 0.8 = 1 - e-(1/15)x.

The next step is to solve for x: 0.2 = e-(1/15)x. Taking the natural logarithm of both sides, we get ln(0.2) = -(1/15)x. Solving for x gives x = -15 * ln(0.2). Calculating this gives an approximate value for the 80th percentile for the time between calls, which is equivalent to 22.2 seconds, which corresponds to option (a).

User Jcccn
by
8.7k points