Question

If the specific heat of methanol is 2.51 J/g°C, how many joules are necessary to raise the temperature of 50.0 g methanol from 20.0 °C to 60.0 °C?

a) 502.0 J
b) 627.5 J
c) 753.0 J
d) 878.5 J

Answer 1

The amount of heat required to raise the temperature of 50.0 g methanol from 20.0 °C to 60.0 °C is 502.0 J.

Step-by-step explanation:

To calculate the amount of heat required to raise the temperature of methanol from 20.0 °C to 60.0 °C, we can use the formula:

Q = mcΔT

where Q is the amount of heat, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.

Plugging in the values, we have:

Q = (50.0 g)(2.51 J/g°C)(60.0 °C - 20.0 °C) = 5,020 J

Therefore, the correct answer is option a) 502.0 J.