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If the temperature is -3°F at 10:00 pm and the temperature falls 4°F overnight, what is the resultant temperature?

a) -7°F
b) -8°F
c) -11°F
d) -14°F

User Ray Burns
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1 Answer

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Final answer:

When the temperature drops 4°F from an initial temperature of -3°F, the resultant temperature is -7°F.

Step-by-step explanation:

If the temperature is -3°F at 10:00 pm and the temperature falls 4°F overnight, the resultant temperature can be calculated by subtracting 4°F from -3°F. To do this mathematically, you would express the temperature drop as -4°F since it is a decrease, and then add this value to the initial temperature:

-3°F + (-4°F) = -7°F

The resultant temperature would therefore be -7°F.

User Jack Henahan
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