Question

A windmill has an initial angular momentum of 8550 kg⋅m2/s . the wind picks up, and 6.06 s later the windmill's angular momentum is 9750 kg⋅m2/s .what was the torque acting on the windmill, assuming it was constant during this time?

Answer 1

The constant torque that acted on the windmill to change its angular momentum from 8550 kg·m2/s to 9750 kg·m2/s over a period of 6.06 seconds is approximately 198.02 N·m.

Step-by-step explanation:

Given that a windmill has an initial angular momentum of 8550 kg·m2/s and a final angular momentum of 9750 kg·m2/s after 6.06 seconds, we need to determine the constant torque that acted on the windmill. The change in angular momentum ΔL is given by the final angular momentum minus the initial angular momentum, which is 9750 kg·m2/s - 8550 kg·m2/s = 1200 kg·m2/s.

Torque (τ) can be calculated using the formula τ = ΔL / Δt, where Δt is the change in time. Plugging in the values we get τ = 1200 kg·m2/s / 6.06 s, which results in a constant torque of approximately 198.02 N·m acting on the windmill.