Final answer:
Complete nondisjunction during meiosis I results in four aneuploid gametes because the homologous chromosomes either all have an extra or are all missing one chromosome. Nondisjunction in meiosis I does not produce any normal gametes.
Step-by-step explanation:
The correct answer to the question "Complete nondisjunction during the first meiotic division would result in which of the following gametes at the end of meiosis II?" is Four aneuploid gametes. This is because nondisjunction during meiosis I results in one of two scenarios. Either all gametes will have an extra copy of the affected chromosome (n+1), or all will have one fewer (n-1). This occurs because the homologous chromosomes fail to separate during the first meiotic division, leading to two gametes with duplicated chromosomes and two gametes lacking that chromosome. In contrast, nondisjunction during meiosis II, when sister chromatids fail to separate, results in two normal gametes, one with an extra chromosome, and one with a missing chromosome. Therefore, nondisjunction in meiosis I does not result in any normal gametes; instead, it produces four aneuploid gametes.