Final answer:
The volume of the weather balloon at -22.4°C, assuming pressure is held constant, can be found using Charles's Law. None of the answer choices provided match the calculated volume of approximately 11.0 L, which suggests there might be an error in the options given or in the question details.
Step-by-step explanation:
The student's question pertains to the change in volume of a gas within a weather balloon when the temperature drops from 0.00°C to -22.4°C, given that the pressure remains constant. To solve this, we use Charles's Law, which states that for a fixed amount of gas at constant pressure, the volume is directly proportional to its temperature in Kelvins. First, we convert both temperatures to Kelvin by adding 273.15 and then use the formula:
V1/T1 = V2/T2
To find the new volume (V2), we rearrange the equation:
V2 = V1 × (T2/T1)
Inserting the values:
V2 = (12.0 L) × ((251.75 K) / (273.15 K))
After calculating, we obtain:
V2 ≈ 11.0 L
Therefore, none of the options given (A, B, C, D) seems to match the correct answer. It is important for the student to verify the temperature, the volume values or the options provided in the question.