Question

A vendor hangs an 8.8 kg sign in front of his shop with a cable held away from the building by a lightweight pole. the pole is free to pivot about the end where it touches the wall. what is the tension in the cable? express your answer with the appropriate units.

Answer 1

The tension in the cable that supports an 8.8 kg sign is equal to the weight of the sign, which is calculated as 86.24 N.

Step-by-step explanation:

To find the tension in the cable that supports the 8.8 kg sign, we have to consider the forces acting on the system. Assuming the sign is in equilibrium, the force due to gravity (the weight of the sign) must be balanced by the upward tension in the cable. The weight of the sign (W) can be calculated using the equation W = mg, where m is the mass of the sign and g is the acceleration due to gravity (9.8 m/s²).

Thus, W = 8.8 kg × 9.8 m/s² = 86.24 N.

Since there's no information given about the angle of the cable or other forces, and since we're looking for the tension in a vertical direction, we can assume that the tension in the cable is equal to the weight of the sign. Therefore, the tension in the cable is 86.24 N.