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A student performs this experiment and determines that 1.12 g of c o 2 were lost, but based on the limiting reagent calculations, 1.43 g of c o 2 were expected to be lost. what is the percent error for this student's experiment?

User Mdgrech
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1 Answer

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Final answer:

The percent error for the student's experiment, where the actual loss of CO2 was 1.12 g instead of the calculated 1.43 g based on the limiting reagent, is found to be 21.68%.

Step-by-step explanation:

The student's question pertains to an experimental error calculation based on a limiting reagent in a chemical reaction where carbon dioxide (CO2) was lost during the process. The student observed a loss of 1.12 g of CO2, whereas 1.43 g was expected based on stoichiometric calculations. To calculate the percent error, we use the formula:

Percent Error = |(Expected Value - Experimental Value) / Expected Value| × 100%

Substituting the values:

Percent Error = |(1.43 g - 1.12 g) / 1.43 g| × 100%

= |0.31 g / 1.43 g| × 100%

= 21.68%

Therefore, the percent error for this student's experiment is 21.68%.

User Jason James
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