Question

A typical muscle fiber is 2.0 cm long and has a cross-section area of 3.1×10−9m2 . when the muscle fiber is stimulated, it pulls with a force of 1.3 mn .what is the work done by the muscle fiber as it contracts to a length of 1.5 cm ?

Answer 1

The work done by the muscle fiber as it contracts from 2.0 cm to 1.5 cm with a force of 1.3 mN is 6.5×10-6 joules.

Step-by-step explanation:

To calculate the work done by the muscle fiber as it contracts, we can use the formula for work, which is the product of the force exerted by the muscle and the distance over which the force is exerted. In this case, the muscle fiber contracts from 2.0 cm (initial length) to 1.5 cm (final length), which is a contraction of 0.5 cm or 0.005 meters. The force exerted by the muscle fiber is given as 1.3 mN (millinewtons), which is equivalent to 1.3×10-3 newtons.

The work done (W) by the muscle during contraction can be calculated using the formula: W = force × displacement

W = (1.3×10-3 N)(0.005 m)

W = 6.5×10-6 joules (J)

The work done by the muscle fiber as it contracts is 6.5×10-6 joules.