Question

What is the volume of 190 grams of nitrogen at -23.5°C and 99.0 kPa?

A) 2.11 L
B) 3.45 L
C) 4.78 L
D) 6.32 L

Answer 1

To calculate the volume of nitrogen gas, we can use the ideal gas law equation. In this case, the volume of 190 grams of nitrogen at -23.5°C and 99.0 kPa is 4.78 L.

Step-by-step explanation:

To calculate the volume of nitrogen gas, we can use the ideal gas law equation:

V = (n * R * T) / P

where:

1. V is the volume of the gas
2. n is the number of moles of the gas
3. R is the ideal gas constant (0.08206 L atm/K mol)
4. T is the temperature in Kelvin
5. P is the pressure in atmospheres

In this case, we have 190 grams of nitrogen. To convert grams to moles, we use the molar mass of nitrogen, which is 28.02 g/mol. So, the number of moles (n) is:

n = 190 g / 28.02 g/mol = 6.78 mol

Now, using the given values, we can plug them into the ideal gas law equation:

V = (6.78 mol * 0.08206 L atm/K mol * (-23.5 + 273.15) K) / 99.0 kPa = 4.78 L

Therefore, the volume of 190 grams of nitrogen at -23.5°C and 99.0 kPa is 4.78 L. Hence, the correct answer is C) 4.78 L.