Final answer:
The final temperature of the metal after adding 305 J of heat to 71.6 g initially at 20°C is 53.2°C.
So, the correct answer is D.
Step-by-step explanation:
To calculate the final temperature, we can use the formula:
Q = mcΔT
Where Q is the heat energy absorbed or released, m is the mass, c is the specific heat, and ΔT is the change in temperature.
In this case, we have 305 J of heat added to 71.6 g of metal initially at 20°C.
So, using the formula:
Q = mcΔT
305 J = (71.6 g)(0.128 J/(g°C))(T - 20°C)
305 J = 9.1696g(T - 20°C)
T - 20°C = 33.289
T = 53.2°C
Therefore, the final temperature is 53.2°C.
So, the correct answer is D.53.2°C.
Complete question:
The specific heat of a certain type of metal is 0.128 J/(gxC). What is the final temperature if 305 J of heat is added to 71.6 g of the metal, initially at 20°C?
Multiple choice options for this question:
a. 79.1°C
b. 25.4°C
c. 27.8°C
d. 53.2°C