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A spring with a spring constant of 1.8 × 102 n/m is attached to a 1.6 kg mass and then set in motion. what is the period of the mass-spring system? answer in units of s

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Final answer:

The period of the mass-spring system with a spring constant of 1.8 × 10^2 N/m and a 1.6 kg mass is approximately 0.56 seconds.

Step-by-step explanation:

Calculating the Period of a Mass-Spring System

The period of a mass-spring system can be found using the formula for the period T of a simple harmonic oscillator, which is T = 2π√(m/k), where m is the mass of the object attached to the spring and k is the spring constant. In this case, we have a mass m = 1.6 kg and a spring constant k = 1.8 × 102 N/m. Plugging these values into the formula, we get:

T = 2π√(1.6 kg / 1.8 × 102 N/m)

Which gives us:

T = 2π√(0.0088889 kg·m/N)

T = 2π√(0.0088889) s

T approximately equals 0.560 s

Therefore, the period of the mass-spring system is approximately 0.56 seconds.

User Jonas Kongslund
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