Question

If a sphere of radius 8.0 cm carries a uniform volume charge density rho=500 nc/m3, what is the electric field at r=4.0 cm from the center of the sphere?

Answer 1

The electric field at a distance of 4.0 cm from the center of the sphere is 5 × 10^5 N/C.

Step-by-step explanation:

To find the electric field at a distance of 4.0 cm from the center of a sphere, we can use the formula for the electric field due to a uniformly charged sphere:

E = (k * Q * r) / (4πε₀ * R³)

where E is the electric field, k is Coulomb's constant, Q is the total charge of the sphere, r is the distance from the center of the sphere, and R is the radius of the sphere. Plugging in the values, we get:

E = (9 * 10^9 * 500 * 4/3 * π * (0.04)³) / (4 * π * 8³) = 5 × 10^5 N/C