Question

A small particle has charge -5.10 μc and mass 1.30×10−4 kg. it moves from point a, where the electric potential is va = 130 v, to point b, where the electric potential vb = 690 v is greater than the potential at point a. the electric force is the only force acting on the particle. the particle has a speed of 5.50 m/s at point a.

Answer 1

The question pertains to Physics, involving a charged particle's motion between two points with different electric potentials, where its speed changes due to the electric potential difference.

Step-by-step explanation:

The subject of the question is Physics, specifically dealing with the concept of electric potential and its effect on a charged particle moving in an electric field. A particle with a known charge and mass moves between two points with different electric potentials. As there are no other forces acting on the particle, its kinetic energy changes due to the work done by the electric force. Therefore, as the particle moves from a lower potential to a higher potential, it will experience a change in speed. This problem involves the principles of conservation of energy and the relation between potential difference and kinetic energy change.