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A 2.0-kg mass is attached to a spring with a spring constant of 800 n/m and oscillates with an amplitude of 50 cm. what is the ratio of the kinetic energy to the total energy when the displacement is 10 cm?

User Indhira
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Final answer:

The ratio of kinetic energy to total energy when the displacement is 10 cm is 0.

Step-by-step explanation:

To find the ratio of kinetic energy to total energy, we need to calculate the potential energy of the spring at a displacement of 10 cm.

The potential energy of a spring is given by the formula:

U = (1/2)kx^2

where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.

Given that the mass is 2.0 kg and the spring constant is 800 N/m, the potential energy at a displacement of 10 cm (0.1 m) is:

U = (1/2)(800 N/m)(0.1 m)^2 = 4 J

The total energy of the system is the sum of the potential energy and the kinetic energy. At any point in the oscillation, the total energy remains constant:

E = U + KE

Since we know the potential energy is 4 J, we can find the kinetic energy:

E = 4 J + KE

To find the kinetic energy, we can use the equation:

KE = (1/2)mv^2

where m is the mass and v is the velocity.

At a displacement of 10 cm, the object is at the maximum displacement and momentarily at rest. Therefore, the kinetic energy is zero.

The ratio of kinetic energy to total energy is:

Ratio = KE/E = 0/4 = 0

User Iargin
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