Question

A 0.150 m solution of an enantiomerically pure chiral compound d has an observed rotation of 0.18 degrees in a 1-dm sample container. the molar mass of the compound if 176.0g/mol. what is the observed rotation if this solution is mixed with an equal volume of solution that is 0.150m in, the enantiomer is d?

Answer 1

After mixing equal volumes of solutions containing enantiomerically pure dextrorotatory and levorotatory enantiomers, the net observed rotation will be zero as their effects cancel each other out.

Step-by-step explanation:

The question is about determining the observed rotation of a chiral compound after two enantiomerically pure solutions, each containing one of the two enantiomers, are mixed in equal volumes. The original solution of dextrorotatory enantiomer (d) has an observed rotation of 0.18 degrees. When this solution is mixed with an equal volume of solution containing the levorotatory enantiomer (1), which would have an equal but opposite observed rotation, the net observed rotation becomes zero. This is because enantiomers rotate the plane of polarized light with equal magnitude but in opposite directions, and when present in equal concentrations, their rotations cancel each other out.