Question

A 0.17-kg rubber egg bounces off an actor's roof, remaining in contact with it for 66 ms while changing the egg's velocity from 29.3 m/s directly toward the roof to 11.6 m/s directly away from it. find the magnitude of the average force applied to the egg by the roof. (be careful with units!)

Answer 1

The magnitude of the average force applied to the egg by the roof is approximately 217 N.

Step-by-step explanation:

To calculate the magnitude of the average force applied to the egg by the roof, we can use the impulse-momentum equation:

F * Δt = m * Δv

Where F is the average force, Δt is the time of contact, m is the mass, and Δv is the change in velocity. Plugging in the values given:

F * 0.066 = 0.17 * (11.6 - (-29.3))

Simplifying the equation, we find that the magnitude of the average force applied to the egg by the roof is approximately 217 N.