Question

To rent a certain meeting room, A college charges a reservation fee of $45 and an additional fee of $9.30 per hour. The chemistry club wants to spend less than $110.10 on renting the meeting room.

Answer 1

The chemistry club can rent the meeting room for less than 7 hours to stay within their budget of $110.10, based on the college's fixed reservation fee of $45 and additional hourly fee of $9.30.

Step-by-step explanation:

The question asks us to determine how many hours the chemistry club can rent the meeting room without exceeding their budget of $110.10. We have a basic cost structure with a fixed fee and a variable fee based on the number of hours. The college charges a reservation fee of $45 and an additional fee of $9.30 per hour.

The equation to calculate the total cost (C) for renting the room for 'h' hours is given by:

C = 45 + 9.30h

Since the chemistry club wants to spend less than $110.10, we set the inequality:

45 + 9.30h < 110.10

To solve for 'h', we'll subtract 45 from both sides of the inequality:

9.30h < 110.10 - 45

When we do the subtraction, we get:

9.30h < 65.10

Now, we'll divide both sides by 9.30 to solve for 'h':

h < 65.10 / 9.30

After performing the division, we find out the maximum number of hours the chemistry club can rent the meeting room:

h < 7

Therefore, the chemistry club can rent the room for less than 7 hours to ensure they spend less than $110.10.