Final answer:
In a Hardy-Weinberg population with a 20% frequency of allele A, the frequency of the a allele is 80%.
Step-by-step explanation:
The Hardy-Weinberg principle is a fundamental concept in Biology that predicts the genetic variation in a Weinberg population that is not subject to evolutionary forces. In a Hardy-Weinberg population with a frequency of 20% for allele A, we can calculate the frequency of the allele 'a' using the equation p + q = 1, where 'p' represents the frequency of the dominant allele (A in this case) and 'q' represents the frequency of the recessive allele (a). Given that 'p' for allele A is 0.20, we calculate 'q' by subtracting it from 1, which means q = 1 - p = 1 - 0.20 = 0.80 or 80%.