Question

Put the superoxide

reacts with carbon dioxide formed potassium carbonate and oxide 3KO2+3CO2→2K
2CO3+3O how much oxygen
2O2could be produced from 2.5 g of 2KO2and 4.5 g of 2CO2?
a) 2.25 g
b) 3.75 g
c) 4.50 g
d) 5.25 g

Answer 1

To determine how much oxygen (O2) can be produced, use stoichiometry to calculate the moles of O2 produced from the given masses of 2KO2 and 2CO2.

Step-by-step explanation:

In the given reaction, 3KO2 + 3CO2 → 2K2CO3 + 3O2, it can be observed that 3 moles of KO2 react with 3 moles of CO2 to produce 2 moles of K2CO3 and 3 moles of O2. To determine how much oxygen (O2) can be produced, we need to find the limiting reactant. We can use stoichiometry to calculate the moles of O2 produced from the given masses of 2KO2 and 2CO2.

First, calculate the moles of 2KO2 and 2CO2 using their molar masses. Then, compare the moles obtained to determine which reactant is limiting. Finally, use the ratio of the coefficients from the balanced equation to calculate the moles of O2 produced.

Using this information, we can determine the mass of O2 produced from the moles of O2 generated. The answer is option b) 3.75 g.