Final answer:
The given statement is false for all possible combinations of truth values of the variables F and S.
Step-by-step explanation:
The given statement is: (Fv~S)⊃~(Sv~F)
To construct a truth table for this statement, we need to consider all possible combinations of truth values for the variables F and S.
We can start by listing all possible values of F and S:
- F = T, S = T
- F = T, S = F
- F = F, S = T
- F = F, S = F
Next, we substitute these values into the given statement and evaluate the truth value of the statement for each combination:
- (T v ~T)⊃~(T v ~T) = (T v F)⊃~(T v T) = T⊃~T = F
- (T v ~F)⊃~(F v ~T) = (T v T)⊃~(F v F) = T⊃~F = F
- (F v ~T)⊃~(T v ~F) = (F v F)⊃~(T v T) = T⊃~T = F
- (F v ~F)⊃~(F v ~F) = (F v T)⊃~(F v T) = T⊃~T = F
Based on the truth table, we can conclude that the given statement is false for all possible combinations of truth values of F and S.