Question

400 g of a metal absorbs 10000 J of heat energy and its temperature rises from 20.0 degrees Celsius to 103 degrees Celsius. What is the specific heat of the metal?

Answer 1

The specific heat of the metal is calculated using the formula q = mc\u2206T, where the heat energy (q) absorbed is 10000 J, the mass (m) is 400 g, and the change in temperature (\u2206T) is 83 \u00b0C. Solving for the specific heat (c) gives a value of 0.301 J/g\u00b0C.

Step-by-step explanation:

To determine the specific heat of the metal, we use the formula:

q = mc\u2206T

where:

• q is the heat energy absorbed or released (in joules, J)
• m is the mass of the substance (in grams, g)
• c is the specific heat capacity (in joules per gram per degree Celsius, J/g\u00b0C)
• \u2206T is the change in temperature (in degrees Celsius, \u00b0C)

From the information provided:

• The mass of the metal, m, is 400 g
• The heat energy absorbed, q, is 10000 J
• The change in temperature, \u2206T, is 103 \u00b0C - 20 \u00b0C = 83 \u00b0C

Now, we solve for the specific heat capacity, c:

10000 J = 400 g * c * 83 \u00b0C

c = 10000 J / (400 g * 83 \u00b0C)

c = 10000 J / 33200 g\u00b0C

c = 0.301 J/g\u00b0C

Therefore, the specific heat of the metal is 0.301 J/g\u00b0C.