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300.0 g of water is at 12.0 ºC. The water absorbs 4016 J of heat energy. What is the new temperature of the water?

a) 3.2 ºC
b) 15.2 ºC
c) 8.8 ºC
D) 13.1 ºC

1 Answer

6 votes

Final answer:

The new temperature of the water is 8.19 °C. The new temperature can be found by subtracting the change in temperature from the initial temperature new temperature of the water is 12.0 °C - 3.81 °C, = 8.19 °C.

Step-by-step explanation:

To find the new temperature of the water, we can use the formula q = mcΔT, where q is the heat absorbed by the water, m is the mass of the water, c is the specific heat capacity of the water, and ΔT is the change in temperature. Rearranging the formula, we have ΔT = q / (mc). Plugging in the given values, we have ΔT = 4016 J / (300.0 g * 4.184 J/(g·°C)). Solving for ΔT, we get ΔT = 3.81 °C.

The initial temperature of the water was 12.0 °C, so the new temperature can be found by subtracting the change in temperature from the initial temperature. Therefore, the new temperature of the water is 12.0 °C - 3.81 °C = 8.19 °C.

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