Question

What is written to the monitor by the following section of code:

String strA = new String("Roasted ");
String strB = new String("Acorns ");
strA = strB;
if ( strA == strB )
System ("Two copies of a reference.");
else
System ("Two different references.");

Answer 1

The code checks if strA and strB refer to the same object after strA is assigned to strB. It will print "Two copies of a reference." because they become the same reference after the assignment.

Step-by-step explanation:

The code provided is checking whether strA and strB are the same reference after strA is reassigned to strB. Initially, two different String objects are created with the contents "Roasted " and "Acorns " respectively. Then, strA is made to reference the same object as strB.

After this assignment, when we compare strA and strB with the '==' operator, it checks for reference equality. Since strA now points to the same object as strB, the condition strA == strB will be true. Hence, "Two copies of a reference." would be written to the monitor. The provided code snippet is missing the System.out.println() method for output and contains only the message strings. The corrected line should be System.out.println("Two copies of a reference.").