Final answer:
Superman's velocity upon hitting the ground after falling from the Eiffel Tower for 8.13 seconds would be approximately 79.674 m/s. Using the free-fall formula, the height of the Eiffel Tower can be approximated to be around 324 meters.
Step-by-step explanation:
The question asks about two scenarios involving physics principles: calculating Superman's velocity as he hits the ground and determining the height of the Eiffel Tower based on the free-fall time given.
A. Superman's Velocity Upon Impact
When Superman hits the ground after falling for 8.13 seconds, we can use the formula for velocity in free fall (neglecting air resistance):
v = gt, where g is the acceleration due to gravity (9.8 m/s2 on Earth), and t is the time in seconds. Thus, v = 9.8 m/s2 × 8.13 s calculates to approximately 79.674 m/s.
B. Height of the Eiffel Tower
To find the height of the Eiffel Tower, we use the formula for distance in free fall: d = ½ gt2. Substituting the values, we get d = ½ × 9.8 m/s2 × (8.13 s)2 which results in approximately 324.09285 meters. Therefore, the Eiffel Tower can be approximated to be 324 meters tall based on the given time of Superman's fall.