The dimensions of the forest portrait are:
Length: (2/3)w_s
Width: w_s
To find the dimensions of the forest portrait, we can use the information provided in the question. The length, l, of the forest portrait is 1/3 smaller than the width of the sea portrait. Let's denote the width of the sea portrait as w_s. Then, the length of the forest portrait, l_f, is given by:
l_f = w_s - (1/3)w_s
= w_s - w_s/3
= (2/3)w_s
So, the length of the forest portrait is 2/3 of the width of the sea portrait. The width of the forest portrait, w_f, is the same as the width of the sea portrait, w_s.
Therefore, the dimensions of the forest portrait are:
Length: (2/3)w_s
Width: w_s
Complete question.
Luis painted a sea portrait and a forest portrait. The paintings have different dimensions but the same perimeter. The length, l, of the forest 1/3 smaller than the width of the sea portrait. What are the dimensions of the forest portrait?