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Luis painted a sea portrait and a forest portrait. The paintings have different dimensions but the same perimeter. The length, l, of the forest portrait is 20% greater than the length of the sea portrait. What are the dimensions of the forest portrait?

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The dimensions of the forest portrait are:

Length: (2/3)w_s

Width: w_s

To find the dimensions of the forest portrait, we can use the information provided in the question. The length, l, of the forest portrait is 1/3 smaller than the width of the sea portrait. Let's denote the width of the sea portrait as w_s. Then, the length of the forest portrait, l_f, is given by:

l_f = w_s - (1/3)w_s

= w_s - w_s/3

= (2/3)w_s

So, the length of the forest portrait is 2/3 of the width of the sea portrait. The width of the forest portrait, w_f, is the same as the width of the sea portrait, w_s.

Therefore, the dimensions of the forest portrait are:

Length: (2/3)w_s

Width: w_s

Complete question.

Luis painted a sea portrait and a forest portrait. The paintings have different dimensions but the same perimeter. The length, l, of the forest 1/3 smaller than the width of the sea portrait. What are the dimensions of the forest portrait?

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