Question

Using the equilibrium constant Kc for the decomposition of 2SO3(g) into 2SO2(g) and O2(g) is 0.230. What are the equilibrium concentrations of SO3, and SO2 in a mixture that initially contained only SO3 at a concentration of 5.09M?

Answer 1

The equilibrium concentrations of SO3 and SO2 in the given mixture are 0.93 M and 1.86 M, respectively.

Step-by-step explanation:

To find the equilibrium concentrations of SO3 and SO2 in the given mixture, we can use the given equilibrium constant Kc and the initial concentration of SO3.

The equilibrium constant expression for the decomposition of 2SO3(g) into 2SO2(g) and O2(g) is:

Kc = [SO2]^2[O2] / [SO3]^2

Substituting the known values:

Kc = (0.230) = (x)^2(2x) / (5.09)^2

Simplifying the equation:

x = 0.93 M

Therefore, at equilibrium, the concentration of SO3 is 0.93 M and the concentration of SO2 is 2x = 2(0.93) = 1.86 M.