Question

Int func(int n, double d)

{
int j = n;
double sum = 0;
while( j >= 0)
{
sum += d;
}
return sum;
}
C++ Programming: Program Design Including Data Structures, Seventh Edition 35
With arguments 7and 2.0
a) returns 7*2
b) returns 7+2
c) returns 7!
d) This is infinite loop

Answer 1

The function provided in the question contains an infinite loop due to the unmodified loop variable, which causes the program to add the variable 'd' to 'sum' without ever terminating.

Step-by-step explanation:

The provided code in the question has a function func that takes two arguments, an integer n and a double d. However, upon a closer inspection of the function, you can observe that there is an infinite loop. The reason for this is that within the while loop, the condition j ≥ 0 always evaluates to true and the variable j is never modified or decremented, making the loop run indefinitely. Therefore, the function does not return a finite sum, but instead, the loop continues to add the value of d to the sum endlessly.

The given C++ function is:

int func(int n, double d){ int j = n; double sum = 0; while( j >= 0){ sum += d; } return sum; }

In this function, a while loop is used with the condition j >= 0. The loop will continue as long as the value of j is greater than or equal to 0. However, the value of j is initialized to n and there are no statements within the loop block that update the value of j. This means that if n is a positive number, the condition j >= 0 will always be true, resulting in an infinite loop.

So, the correct answer is d) This is an infinite loop.