Final answer:
The algebraic equation for term 1 is 8 and term 2 is 11 is a_n = 8 + (n-1)(3).
Step-by-step explanation:
The algebraic equation for term 1 is 8 and term 2 is 11 can be found by using the arithmetic progression formula:
an = a1 + (n-1)d
where an represents the nth term, a1 is the first term, n is the number of terms, and d is the common difference.
In this case, a1 is 8 and a2 is 11. We can substitute these values into the formula:
11 = 8 + (2-1)d
Simplifying, we get:
3 = d
Therefore, the algebraic equation for this arithmetic sequence is:
an = 8 + (n-1)(3)