The value of the server after 12 years of use would be $12,400.
We can use the given information to determine the equation that relates the value of the server v with the time passed t. Since the value of the server depreciates linearly with time, we can use the slope-intercept form of a linear equation:
v = mt + b
where m is the slope (the rate of depreciation) and b is the y-intercept (the value of the server when it was new).
To find the slope, we can use the two given data points: (0, value when new) and (4, 41400). The change in value over 4 years is:
change in value = current value - value 4 years ago
= 23000 - 41400
= -18400
The rate of depreciation is the change in value divided by the time interval:
m = (change in value) / (time interval)
= -18400 / 4
= -4600
Therefore, the equation that relates the value of the server v with the time passed t is:
v = -4600t + b
To find the value of b, we can use the fact that the current value of the server is $23,000 when t = 10 (since the server has been used for 10 years). Substituting these values into the equation, we get:
23000 = -4600(10) + b
b = 68000
Therefore, the equation that relates the value of the server v with the time passed t is:
v = -4600t + 68000
The value of the server when it was new would be $68,000.
To find the value of the server after 12 years of use, we can substitute t = 12 into the equation:
v = -4600(12) + 68000
v = 12400
Therefore, the value of the server after 12 years of use would be $12,400.