Final answer:
The magnitude of the flywheel's angular momentum is 39.7 kg·m²/s.
Step-by-step explanation:
The angular momentum of a flywheel is given by the equation:
Angular momentum (L) = Moment of inertia (I) x Angular velocity (ω)
The moment of inertia of a solid cylindrical flywheel can be calculated using the equation:
Moment of inertia (I) = 0.5 x mass x radius^2
Plugging in the values given in the question:
I = 0.5 x 15 kg x (1.4 m)^2
= 14.7 kg·m²
The magnitude of the flywheel's angular momentum can be calculated as:
L = 14.7 kg·m² x 2.7 rad/s
= 39.7 kg·m²/s
Therefore, the magnitude of the flywheel's angular momentum is 39.7 kg·m²/s.