Answer:
f(x) = 1 + x - (√6)x²
f'(x) = 1 - 2x√6 = 0
2x√6 = 1
x = 1/(2√6) = (1/12)√6
f(x) = 1 + (1/12)√6 - (√6)((1/12)(√6))²
= 1 + (1/12)√6 - (√6)(6/144)
= 1 + (1/12)√6 - (1/24)√6
= 1 + (1/24)√6
= about 1.1021
(which is close to part (b))
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