Question

A child throws a piece of candy corn directly up with an initial velocity of 3.8 m/s. If the starting height of the candy was 2.2 meters, what will be the height of the candy after 0.3 seconds? Use a = -9.8m/s/s

Answer 1

Answer:
2.89855 meters

Steps:
Let’s use the
Δx = Vi * t + 1/2 * a * t^2
Δx is short for change in position therefore

Xf - Xi = Vi * t + 1/2 * a * t^2

We are given the initial position, initial velocity, acceleration, and time.

Let’s solve for final position (Xf).

Xf - 2.2 = 3.8 * 0.3 + 1/2 * -9.81 * 0.3^2
Xf - 2.2 = 1.14 + 1/2 * -9.81 * 0.3^2
Xf - 2.2 = 1.14 + -4.905 * 0.09
Xf - 2.2 = 1.14 + −0.44145
Xf - 2.2 = 1.14 - 0.44145
Xf - 2.2 = 0.69855
Xf = 0.69855 + 2.2
Xf = 2.89855