Question

a student moves along the boundary of a square field of side 10 m in 40 second if we started from one of the coordinates of the square what will be the magnitude of thie displacement of the student at the end of two means in 22nd from his initial position​

Answer 1

The magnitude of the student's displacement at the end of two minutes and 22 seconds is 10m x sqrt(2)

Step-by-step explanation:

To find the magnitude of the student's displacement, we can use the Pythagorean theorem. Since the student moves along the boundary of a square field, their displacement is the diagonal of the square.

The diagonal of a square with side length 10m can be calculated using the formula: diagonal = side length x sqrt(2). So, the diagonal of this square field is 10m x sqrt(2).

After two means in 22 seconds, the student is still on the boundary of the square, so their displacement is still the diagonal of the square. Therefore, the magnitude of the student's displacement at the end of two minutes and 22 seconds is 10m x sqrt(2).