Question

Oxygen gas reacts with powdered aluminum according tot he reaction:

4 Al(s) + 3 O₂(g) → 2 Al₂O₃(s)

WHat volume of O₂ gas (in L), measured at 782 mmHg and 25°C completely reacts with 67.9 g Al?

Answer 1

To determine the volume of O₂ gas needed to react with 67.9 g of aluminum, we must first convert the mass of Al to moles, use the stoichiometry of the reaction to calculate moles of O₂, and then apply the ideal gas law with the given pressure and temperature conditions.

Step-by-step explanation:

The question asks about the volume of O₂ gas required to react with a given mass of aluminum (Al) at a specific pressure and temperature. To find the volume of oxygen, we can use the stoichiometry of the balanced chemical equation provided along with the ideal gas law equation: PV = nRT.

First, we need to determine the number of moles of Al using its molar mass, and then use the stoichiometry of the reaction to find the moles of O₂ required. Knowing the moles of oxygen and using the given pressure (782 mmHg, which we convert to atm) and temperature (25°C, which needs to be converted to Kelvin), we can then apply the ideal gas law to calculate the volume of O₂ gas.