The correct responses are as follows;
First part; a = 11
Question 8; 5,940°
Question 9; 2·x + 45 = 180°
Question 10; 82.45°
Question 11; 47.46°
Question 12; 3, 4, and 5
Question 13;
Part A; 5 miles
Part B; 4 miles
Part C; miles
The details of the method used to arrive at the above responses are presented as follows;
The measure of an interior angle of a regular 9 sided polygon is 140°, therefore;
m∠a = (8·z + 52)°
m∠a = 140°
(8·z + 52)° = 140°
z = (140 - 52)/8
(140 - 52)/8 = 11
a = 11
Question 8: The sum of all interior angles of a 35-sided regular polygon is 5,940°. This is because the formula for the sum of interior angles of a polygon with n sides is (n - 2) × 180°.
(35 - 2) × 180 = 5940
Question 9: The equation that could be used to determine the degree measure of one of the congruent angles is 2·x + 45 = 180. This is because the sum of the angles of a triangle is 180°, and since one angle is 45° and the other two are congruent, we can write 45 + x + x = 180 and simplify it to 2·x + 45 = 180.
Question 10: The measure of the exterior angle to ∠X is 82.45°. This is because the exterior angle of a triangle is equal to the sum of the opposite interior angles, and since m∠Y = 43.85° and m∠Z = 38.6°, we can write 43.85 + 38.6 = 82.45.
Question 11: The value of m∠Y is 47.46°. This is because angles X and Y are supplementary, which means they add up to 180°, and since m∠X = 132.54° and m∠Y = (m - 15)°, we can write 132.54 + (m - 15) = 180 and solve for m to get m = 62.46. Then, we can substitute m into m∠Y to get (62.46 - 15)° = 47.46°.
Question 12: The set of side measurements that could be used to form a right triangle is 3, 4, 5. This is because they satisfy the Pythagorean theorem, which states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides, and since 3² + 4² = 5², they form a right triangle.
Question 13: Part A: The shortest distance, in miles, from Euclid Elementary School to Math Middle School is 5. This is because we can use the distance formula, which is derived from the Pythagorean theorem, to find the length of the line segment that connects the two schools on the coordinate plane.
The distance formula is d = √((x₂ - x₁)² + (y₂ - y₁)²), where (x₁, y₁) and (x₂, y₂) are the coordinates of the two points. Since Euclid Elementary School is at (−4, 1) and Math Middle School is at (1, 1), we can plug in the values and get d = √((1 - (-4))² + (1 - 1)²) = √(25 + 0) = √(25) = 5.
Part B: The shortest distance, in miles, from Euclid Elementary School to Hypotenuse High School is 4. This is because we can use the same distance formula as in Part A, but with different coordinates. Since Euclid Elementary School is at (−4, 1) and Hypotenuse High School is at (−4, −3), we can plug in the values and get d = √((-4 - (-4))² + (-3 - 1)²) = √(0 + 16) = √(16) = 4.
Part C: The shortest distance, in miles, from Math Middle School to Hypotenuse High School is about 6.4. This is because we can use the same distance formula as in Part A, but with different coordinates. Since Math Middle School is at (1, 1) and Hypotenuse High School is at (−4, −3), we can plug in the values and get d = √((-4 - 1)² + (-3 - 1)²) = √(25 + 16) = √(41) ≈ 6.4