The average number of games played in the World Series is 5.70 games.
The probability that the Atlanta Braves win the World Series is 0.636.
(a) Average number of games played regardless of winner:
To calculate the average number of games played regardless of winner, we can use the following formula:
Expected number of games played = (1 * P(1 game) + 2 * P(2 games) + ... + 7 * P(7 games))
where P(n games) is the probability that the series ends in n games.
To calculate P(n games), we can use the following recursive formula:
P(n games) = P(Atlanta wins game n) * P(Atlanta wins series in n-1 games) + P(Atlanta loses game n) * P(Atlanta loses series in n-1 games)
for n = 2 to 7.
Using the given probabilities of Atlanta winning each game, we can calculate the following probabilities:
P(1 game) = 0
P(2 games) = 0.1344
P(3 games) = 0.2128
P(4 games) = 0.1568
P(5 games) = 0.1848
P(6 games) = 0.144
P(7 games) = 0.0672
Substituting these values into the expected number of games played formula, we get:
Expected number of games played = (1 * 0 + 2 * 0.1344 + 3 * 0.2128 + 4 * 0.1568 + 5 * 0.1848 + 6 * 0.144 + 7 * 0.0672) = 5.70 games
Therefore, the average number of games played in the World Series is 5.70 games.
(b) Probability that the Atlanta Braves win the World Series:
To calculate the probability that the Atlanta Braves win the World Series, we can sum the probabilities that the series ends in 4, 5, 6, or 7 games, since those are the only ways for Atlanta to win.
Probability of Atlanta winning the World Series = P(4 games) + P(5 games) + P(6 games) + P(7 games)
We already calculated these probabilities in part (a), so we can simply substitute them into the formula:
Probability of Atlanta winning the World Series = 0.1568 + 0.1848 + 0.144 + 0.0672 = 0.636
Therefore, the probability that the Atlanta Braves win the World Series is 0.636.