Question

What is the equilibrium constant expression of 2 N₂O₅(g) ↔ 4 NO₂(g) + O₂(g)?

a. K = ([NO₂]⁴[O₂])/[N₂O₅]²
b. K = ([NO₂]²[O₂])/[N₂O₅]
c. K = ([NO₂]⁴[O₂]²)/[N₂O₅]³
d. K = ([NO₂][O₂])/[N₂O₅]²

Answer 1

The correct equilibrium constant expression for the given reaction is K = ([NO₂]⁴[O₂])/[N₂O₅]².

Step-by-step explanation:

The equilibrium constant expression for the reaction 2 N₂O₅(g) ↔ 4 NO₂(g) + O₂(g) is represented by K = ([NO₂]⁴[O₂])/[N₂O₅]². In this expression, the concentrations of the products (NO₂ and O₂) are each raised to the power of their coefficients in the balanced equation, and the concentration of the reactant (N₂O₅) is squared because of its coefficient. Hence, The correct equilibrium constant expression for the given reaction is K = ([NO₂]⁴[O₂])/[N₂O₅]².